Help with reactance, power, and resonance?

A power supply can be modeled as a source of emf in series with both a resistance of 10 ohms and an inductive reactance of 5 ohms. To obtain the max power delivered to the load, the load should have a resistance of 10 ohms, an inductive reactance of zero and a capacitve reactance of 5 ohms.

a) with this load is the circuit in resonance

b) what fraction of the average power put out by the source emf is delivered to the load

c) to increase the fraction of the power delived to the load, how could the load be changedHelp with reactance, power, and resonance?
(a) Yes (X of l) = (X of c) = 5 ohms. The two reactances cancel each other allowing maximum current flow possible with the existing resistance.

(b) 1/1, 100% Edit: Corrected to 1/2, 50%.

(c) Any change in the load would result in a decrease in the power delivered to the load.



Edit: After reconsideration I stand corrected on part (b) by answerer SBJV. One half the power put out by the source emf is dissipated in the internal 10 ohm resistance of the power supply.Help with reactance, power, and resonance?
a) dunno

b) 1/2 of the power is sent to the load...remember the 10 ohms inside the power supply is still consuming power...the 10 ohms at the load receives the other half of the power.

c)nothing...unless you can remove the resistance and inductance of the source there's nothing else you can do..